Vier Vijf Mei

Tijdens de Nationale Herdenking op 4 mei herdenken wij allen – burgers en militairen – die in het Koninkrijk der Nederlanden of waar ook ter wereld zijn omgekomen of vermoord sinds het uitbreken van de Tweede Wereldoorlog, in oorlogssituaties en bij vredesoperaties.

Bron: De Achttien Dooden – Jan Campert – Koninklijke Bibliotheek

Thunderbird outlook hotmail messages appear twice in SENT-folder

How can I keep sent messages from appearing twice in the ” sent ” folder. I am using outlook.com and hotmail.com e-mail addresses with IMAP.
Each time I send a message with Thunderbird the sent message is put in the “sent” folder two times.
What setting needs to be changed to in order to have only one copy of the message put in the “sent” folder?

The answer:
Outlook/Hotmail and gmail automatically put copies of sent mail in the imap sent folder. If you have settings to also keep a copy then two are being put in the sent folder.

right click on imap mail account in Folder Pane
select 'Settings'
select 'Copies & Folders'
in 'When sending messages, automatically:'
uncheck : 'Place a copy in:'
click OK

Solution was found here.
Have a nice day!

MSXML2.ServerXMLHTTP and TLS1.2

Okay, so most webservers now have TLS 1.0 and 1.1 disabled, which of course causes code to fail. Also the case for a classic ASP script using MSXML2.ServerXMLHTTP, so Google to the rescue and found this:

It was, surprisingly, easy to convert my existing code in the actual application to use WinHTTP, which appears to work properly enforcing TLS 1.2 on all calls from XP POSReady and Windows 10 (the OS’s where this application will be deployed).

While this isn’t an answer as to why POSReady and XMLServerHTTP calls try to use TLS 1.0 on the first call (despite the registry stating that’s not desirable), it is an acceptable workaround.

For others who may stumble upon this and are hesitant, converting my code was as simple as this:

Set XMLReceive = CreateObject("Msxml2.DOMDocument.6.0")
Set XMLServer = CreateObject("Msxml2.ServerXMLHTTP.6.0")
XMLServer.setTimeouts ResolveTimeoutMs, ConnectTimeoutMs, SendTimeoutMs, ReceiveTimeoutMs

XMLServer.setRequestHeader "User-Agent", "My XML App V1.0"
XMLServer.setRequestHeader "Content-type", "text/xml"
XMLServer.Open "POST", Server_Address, False
XMLServer.send (My_XML_Request_String_or_XML_Document)
Failure = (XMLServer.Status <> 200)
If Not Failure Then XMLReceive.loadXML (XMLServer.ResponseXML.XML)

to:

Set XMLServer = CreateObject("WinHttp.WinHttpRequest.5.1")
Set XMLReceive = CreateObject("Msxml2.DOMDocument.6.0")
XMLServer.setTimeouts ResolveTimeoutMs, ConnectTimeoutMs, SendTimeoutMs, ReceiveTimeoutMs

'force TLS 1.2
XMLServer.Option(9) = 2048
XMLServer.Option(6) = True

XMLServer.Open "POST", Server_Address, False
XMLServer.setRequestHeader "User-Agent", "My XML App V1.0"
XMLServer.setRequestHeader "Content-type", "text/xml"
XMLServer.send (My_XML_Request_String_or_XML_Document)
Failure = (XMLServer.Status <> 200)
If Not Failure Then XMLReceive.loadXML (XMLServer.ResponseText)

Good luck!

update july 2021: to be clear, the original link to the original discussion is here with even more details.
Thank you Montclair for providing the solution.